this post was submitted on 19 May 2025
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I'll be drying the silver out and weighing it sometime in the next couple days. Closest guess when I do gets bragging rights! (And absolutely nothing else)

The scale was zeroed with the beaker empty, and it contains only water and silver (and a trace amount of copper nitrate). If you have a strategy behind your guess, please do share it!

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[–] OfCourseNot@fedia.io 1 points 3 days ago

Ok I think I see what you're doing, but it's still wrong tho. Going, kind of, that way would be:

volume of water = total_volume (silver_mass - slurry_mass) / (silver_mass - water_mass); where silver mass and water mass are the masses of the total volume if it were only that substance alone, ie (volume * density).

With this method you can use the volume of a block of silver instead of powder, which would be more exact as there's air within powdered silver–you can add a bit of water to powdered silver before the volume start to rise–, and also the total volume and mass of the content of the beaker without taking out the water on top.

Sorry if it's not very clear, I'm finishing my lunch break, I can explain/elaborate when I get home.

Btw I've checked my math: 844.4 g silver + 619.6 g water = 1464 g total; 844.4 g silver/ 10.5 gr/cm3 = 80.4 ml silver; 80.4 ml silver + 619.6 ml water = 700 ml total.