this post was submitted on 20 Dec 2024
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[โ€“] pooberbee@lemmy.ml 1 points 2 days ago (1 children)

Yeah, you would get a runtime error calling that member without checking that it exists.

[โ€“] masterspace@lemmy.ca 1 points 1 day ago* (last edited 1 day ago)

Because that object is of a type where that member may or may not exist. That is literally the exact same behaviour as Java or C#.

If I cast or type check it to make sure it's of type Bar rather than checking for the member explicitly it still works:

And when I cast it to Foo it throws a compile time error, not a runtime error: