this post was submitted on 31 Oct 2023
118 points (93.4% liked)
Asklemmy
43962 readers
1495 users here now
A loosely moderated place to ask open-ended questions
Search asklemmy ๐
If your post meets the following criteria, it's welcome here!
- Open-ended question
- Not offensive: at this point, we do not have the bandwidth to moderate overtly political discussions. Assume best intent and be excellent to each other.
- Not regarding using or support for Lemmy: context, see the list of support communities and tools for finding communities below
- Not ad nauseam inducing: please make sure it is a question that would be new to most members
- An actual topic of discussion
Looking for support?
Looking for a community?
- Lemmyverse: community search
- sub.rehab: maps old subreddits to fediverse options, marks official as such
- !lemmy411@lemmy.ca: a community for finding communities
~Icon~ ~by~ ~@Double_A@discuss.tchncs.de~
founded 5 years ago
MODERATORS
you are viewing a single comment's thread
view the rest of the comments
view the rest of the comments
I wish for one electron to disappear from every atom. The net result would be that all atoms would now have a positive charge.
True, it would not only end all life on earth, but also destroy the entire earth. But everything would be positive.
Mandatory XKCD, sort of.
TL;DR
It breaks the whole universe. That's a lot of charge density over a very substantial area.I love that he never even touched proton earth, which would really release some energy. Not sure how bad the collapse of the strong force in that nucleus would be, but I can't imagine that a proton mass 6x more massive than the electron moon would have any less spectacular of a result.
Unfortunately, this is not the case. There are plenty of atoms/molecules that have greater negative ionization states than -1. This wouldn't even make everything neutral.
Captain Pedant... AWAAAAYYYY.
OTOH, if you shifted the ionization state of every single atom, then pretty much every molecule would end up flying apart. You can't form H2O if hydrogen has no electrons at all; hydrogen becomes a single proton.
This is interesting cause I wonder if relatively it'd be like shifting every element in the periodic table one to the left, cause who's to say neutral isn't our current measurement -1, but the orbitals will remain the same hence the shift
Nah, two atoms repelling is not relative. They will do that in every reference frame.
For sure but we have no absolute charge measurements, really for all we know were super positively charged, but so are all our voltometers so everything balances out
No, because we'd be flying apart, or at least our hair would stand up. Negative vs positive are relative, but distance from neutral is not.
Charge and voltage are slightly different, maybe that's where you're caught.
To highlight this we gotta disect your answer a little.
Why does your hair stand up when charged? Because the relationship between each other is similarly charged, and the air less similarly - so its going to have the force of gravity, and those 2 charges affecting it.
If you increase both charges from our 'neutral' by one yes your hair repels itself greater, but so does the air around it.
Similarly if you were on a super charged planet/atmosphere, your hair wouldn't stand up at all cause the atmosphere is charged and you are grounded to it - but the second you change your relative environment to earth you'd probably pass out from the discharge
Stuff stands on end in a vacuum too, though. I don't know about the effect of the presence of air exactly, but the basic phenomenon doesn't depend on it. In electrical engineering where you mostly care about voltage it's convenient to pick a relative ground, but in physics Coulomb's law is pretty unambiguous:
|F| = k~e~*q~1~*q~2~/r^2^
Where q are the charges in question, measured in Coulombs, r is distance and k~e~ is a fundamental constant. For contrast voltage is energy per distance per Coulomb. If we were to add a constant charge to both sides:
|F|=k~e~(q~1~+1)(q~2~+1)/r^2^
|F|r^2^/k~e~=(q~1~+1)(q~2~+1)
|F|r^2^/k~e~=q~1~q~2~+q~1~+q~2~+1
You'll notice that even if we assume no charge was present in the first place, the +1 means that now the two objects will repel. Doing the same thing subtracting from one of them, assuming they're both the same, produces a difference of squares and will decrease repulsion or add attraction, again without requiring any charge in the first place.
The Earth probably does gain a very slight electric charge as it interacts with the solar wind, but it's tiny and I'm not sure if it has ever been measured.