You could use a loop to subtract 2 from the number until it equals one or zero

assert IsEven(-2);

This joke was not written by the dude pictured. The author wrote a book of funny code jokes.

No need to reinvent the wheel. Use the isEven API!

To be fair, the question is "Write a function that simultaneously determines if the number is even and works as a timer"

What you do is use a for loop to generate a million lines for you, then paste it in. Writing it manually is moronic. You can easily make it support numbers above 1,000,000 too this way, talking about scalable

IMO he's ragebaiting

bool isEven(int value) {
  return (int)(((double)value / 2.0) % 1.0) * 100) != 50;
} 

that's some good code right there

I hope that the language's ints are at most 32 bits. For 8 bits it could even be written by hand & the source code for a 32 bit version would only take up avg_line_len * 4GiB space for the source code of the function. But it might take a bit of time to compile a version that supports the full range of 64 or 128 bit ints.

Thanks to goodness, finally. A (giggle & snort) solid algorithm. There ya’s go set yer clocks & go get a haircut.