this post was submitted on 24 Aug 2025
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one could certainly implement something like that in python, something like
time.now - 10 * time.unit.yearDoes this account for leap years?
I don't think this is implemented in the standard datetime library, but in principle overriding sub is easily possible and you can define it as you'd wish.
However, I think subtracting a year is a bit ill defined, because it isn't clear which year you're subtracting given the leap year issue.
If you're subtracting a year from a date, you could just keep the date constant while changing the year, and adjust Feb 29 as needed.