this post was submitted on 08 Nov 2024
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[–] frezik@midwest.social 46 points 2 weeks ago (2 children)

You still have to check that it's sorted, which is O(n).

We'll also assume that destroying the universe takes constant time.

[–] BatmanAoD@programming.dev 42 points 2 weeks ago (2 children)

In the universe where the list is sorted, it doesn't actually matter how long the destruction takes!

[–] groet@feddit.org 13 points 2 weeks ago (1 children)

It actually takes a few trillion years but its fine because we just stop considering the "failed" universes because they will be gone soon™ anyway.

[–] MBM@lemmings.world 8 points 2 weeks ago

Eh, trillion is a constant

[–] FiskFisk33@startrek.website 8 points 2 weeks ago

amortized O(0)

[–] Benjaben@lemmy.world 9 points 2 weeks ago (1 children)

We'll also assume that destroying the universe takes constant time.

Well yeah just delete the pointer to it!

[–] PoolloverNathan@programming.dev 2 points 2 weeks ago

universe.take()