this post was submitted on 06 Jan 2024
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I considered deleting the post, but this seems more cowardly than just admitting I was wrong. But TIL something!

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[–] FishFace@lemmy.world 6 points 10 months ago (1 children)

There is a function which, for each real number, gives you a unique number between 0 and 1. For example, 1/(1+e^x). This shows that there are no more numbers between 0 and 1 than there are real numbers. The formalisation of this fact is contained in the Cantor-Schröder-Bernstein theorem.

[–] lemmington_steele@lemmy.world 1 points 10 months ago (2 children)

ah, but don't forget to prove that the cardinality of [0,1] is that same as that of (0,1) on the way!

[–] FishFace@lemmy.world 3 points 10 months ago

This is pretty trivial if you know that the cardinality of (0, 1) is the same as that of R ;)

[–] sukhmel@programming.dev 1 points 10 months ago (1 children)

Isn't cardinality of [0, 1] = cardinality of {0, 1} + cardinality of (0, 1)? One part of the sum is finite thus doesn't contribute to the result

[–] lemmington_steele@lemmy.world 2 points 10 months ago* (last edited 10 months ago)

technically yes, but the proof would usually show that this works by constructing the bijection of [0,1] and (0,1) and then you'd say the cardinalities are the same by the Schröder-Berstein theorem, because the proof of the latter is likely not something you want to demonstrate every day