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438

Who cares about time complexity (lemmy.world)

submitted 3 days ago by qaz@lemmy.world to c/programmer_humor@programming.dev

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(page 2) 19 comments

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[–] eah@programming.dev 8 points 3 days ago* (last edited 2 days ago) (5 children)

It's got some code duplication. Who can code ~~gulf~~ golf this?

[–] TheLazyNerd@europe.pub 2 points 2 days ago* (last edited 2 days ago)

I'm not too good with java, but it should be something like this:

public static int convertRomanNumeral(string n){Map.of("M","DD","CD","CCCC","D","CCCCC","C","LL","XL","XXXX","L","XXXXX","X","VV","IV","IIII","V","IIIII");.forEach((k,v)->{n=n.replace(k,v);});return n.length();}

[–] ray@sh.itjust.works 3 points 2 days ago (1 children)

public static int convertRomanNumeral(String numeral)
{
  numeral = numeral.replace("M", "DD")
    .replace("CD", "CCCC")
    .replace("D", "CCCCC")
    .replace("C", "LL")
    .replace("XL", "XXXX")
    .replace("L", "XXXXX")
    .replace("X", "VV")
    .replace("IV", "IIII")
    .replace("V", "IIIII");
  return numeral.length();
}

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[–] itsraining@lemmygrad.ml 6 points 3 days ago

According to this code, "CEREAL" is a valid Roman numeral which equals 154. Great job!

[–] BlackEco@lemmy.blackeco.com 3 points 2 days ago (1 children)

Depending on the language, you may be mutating the input value, which isn't great.

[–] qaz@lemmy.world 2 points 2 days ago (1 children)

I'm pretty sure it's Java (due to the syntax and Eclipse editor default color scheme), so that isn't an issue

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[–] SpaceNoodle@lemmy.world 7 points 3 days ago (3 children)

IIV becomes IIIII, hm?

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[–] panda_abyss@lemmy.ca 6 points 3 days ago (2 children)

Should do a regex find all then iterate over each chunk recursively until unchanged.

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[–] fckreddit@lemmy.ml 5 points 3 days ago (1 children)

I just wrote something similar for decoding binary asm instructions.

[–] Valmond@lemmy.world 3 points 3 days ago

If you have the time it's a good solution!

[–] Olap@lemmy.world 5 points 3 days ago

until(original=new) { run convertOriginal }

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