Any answer is correct as long as you don't pick it at random. I'd choose (a) because I'm too lazy to read the other options
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I would think a b c d so 25% O he made a mistake znd forgot to take the bubble answer out. Now we only can pick between aord b c so it would be 33%
Seems my logic is wrong iff i read the rest
The answer is not available. The answer is 0 Percent. Each answer, if chosen, would be incorrect. If 0% was an answer, it would be the correct one despite being a 25% chance. Of course, if one 25% was there, that would be the correct answer.
But if you did randomly choose the 0% option, you'd be correct. So if one of the possible answers was 0% the correct answer would be 25%.
This only produces a paradox if you fall for the usual fallacy that "at random" necessarily means "with uniform probability".
For example, I would pick an answer at random by rolling a fair cubic die and picking a) if it rolls a 1, b) on a 2, d) on a 3 or c) otherwise so for me the answer is c) 50%.
However, as it specifies that you are to pick at random the existence, uniqueness and value of the correct answer depends on the specific distribution you choose.
33% innit
It is 33% if the answer itself is randomly chosen from 25%, 50%, and 60%. Then you have:
If the answer is 25%: A 1/2 chance of guessing right
If the answer is 50%: A 1/4 chance of guessing right
If the answer is 60%: A 1/4 chance of guessing right
And 1/3*1/2 + 1/3*1/4 + 1/3*1/4 = 1/3, or 33.333...% chance
If the answer is randomly chosen from A, B, C, and D (With A or D being picked meaning D or A are also good, so 25% has a 50% chance of being the answer) then your probability of being right changes to 37.5%.
This would hold up if the question were less purposely obtuse, like asking "What would be the probability of answering the following question correctly if guessing from A, B, C and D randomly, if its answer were also chosen from A, B, C and D at random?", with the choices being something like "A: A or D, B: B, C: C, D: A or D"
iis
I choose 75%
Great! I'll hand this to my daughter to annoy her co-students who struggle with probabilitiy ;-)