The space of visible colors is three-dimensional, and the spectrum is missing two dimensions (brightness and saturation). You can’t assign a percentage to that.

[–] MatFi@lemmy.thias.xyz 1 points 8 months ago (1 children)

Well there is wavelength and intensity, an all together it is called a spectrum. No need for a third parameter. Also there are mor than 100% of all colors in there, as a quick check on Wikipedia would reveal..

[–] AbouBenAdhem@lemmy.world 3 points 8 months ago* (last edited 8 months ago) (2 children)

The third parameter is saturation, which comes into play for non-monochromatic (i.e., multiple-wavelength) colors.

[–] LeekWeek@lemmy.world 2 points 8 months ago

I agree

[–] MatFi@lemmy.thias.xyz 1 points 8 months ago (1 children)

There is no such thing as a mono wavelength color. There are only spectral densities. Or in other words electromagnetic radiation / photons distributed over some energy.

[–] Feathercrown@lemmy.world 2 points 8 months ago (1 children)

Is this a weird terminology argument? Because there are definitely ways to produce color that output one specific wavelength of light.

[–] MatFi@lemmy.thias.xyz 1 points 8 months ago

Yes at exactly 0K and without quantumechanics..

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